From the top of a tower, a ball is thrown vertically upward which reaches the ground in 
. A second ball thrown vertically downward from the same position with the same speed reaches the ground in 
. A third ball released, from the rest from the same location, will reach the ground in s.
Text Solution
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(3) Let height of tower be 
and speed of projection in first two cases be 
.
For case-I 
equation 
For case-II : 
Multiplying equation (ii) by 4 we get
equation (i) + equation (iii) we get 
(iv)
For case-III :
Using equation (4) & equation (5)
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